28x^2-46x+16=0

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Solution for 28x^2-46x+16=0 equation:



28x^2-46x+16=0
a = 28; b = -46; c = +16;
Δ = b2-4ac
Δ = -462-4·28·16
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-18}{2*28}=\frac{28}{56} =1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+18}{2*28}=\frac{64}{56} =1+1/7 $

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